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1340314323113 is a prime number
BaseRepresentation
bin10011100000010000111…
…101011000100010101001
311202010120210212020222102
4103200100331120202221
5133424430431314423
62503422031303145
7165556144525163
oct23402075304251
94663523766872
101340314323113
114774735478a7
1219791867aab5
1399511320cbc
1448c2b7b7933
1524ce82e9c28
hex13810f588a9

1340314323113 has 2 divisors, whose sum is σ = 1340314323114. Its totient is φ = 1340314323112.

The previous prime is 1340314323083. The next prime is 1340314323199. The reversal of 1340314323113 is 3113234130431.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 681965459344 + 658348863769 = 825812^2 + 811387^2 .

It is a cyclic number.

It is not a de Polignac number, because 1340314323113 - 214 = 1340314306729 is a prime.

It is not a weakly prime, because it can be changed into another prime (1340314313113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670157161556 + 670157161557.

It is an arithmetic number, because the mean of its divisors is an integer number (670157161557).

Almost surely, 21340314323113 is an apocalyptic number.

It is an amenable number.

1340314323113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1340314323113 is an equidigital number, since it uses as much as digits as its factorization.

1340314323113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7776, while the sum is 29.

Adding to 1340314323113 its reverse (3113234130431), we get a palindrome (4453548453544).

The spelling of 1340314323113 in words is "one trillion, three hundred forty billion, three hundred fourteen million, three hundred twenty-three thousand, one hundred thirteen".