Base | Representation |
---|---|
bin | 1100001100001010110110… |
… | …1000111001110001110000 |
3 | 1202110100000211101221010211 |
4 | 3003002231220321301300 |
5 | 3224044234023104204 |
6 | 44301203350433504 |
7 | 2552231031646222 |
oct | 303025550716160 |
9 | 52410024357124 |
10 | 13403211144304 |
11 | 42a82a72a7363 |
12 | 1605770362894 |
13 | 762bc0667937 |
14 | 344a0c874412 |
15 | 1839ace30804 |
hex | c30ada39c70 |
13403211144304 has 40 divisors (see below), whose sum is σ = 26213038116320. Its totient is φ = 6638584635648.
The previous prime is 13403211144263. The next prime is 13403211144307. The reversal of 13403211144304 is 40344111230431.
It is a super-2 number, since 2×134032111443042 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13403211144307) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6658222 + ... + 8434354.
It is an arithmetic number, because the mean of its divisors is an integer number (655325952908).
Almost surely, 213403211144304 is an apocalyptic number.
It is an amenable number.
13403211144304 is a deficient number, since it is larger than the sum of its proper divisors (12809826972016).
13403211144304 is a wasteful number, since it uses less digits than its factorization.
13403211144304 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1780577 (or 1780571 counting only the distinct ones).
The product of its (nonzero) digits is 13824, while the sum is 31.
Adding to 13403211144304 its reverse (40344111230431), we get a palindrome (53747322374735).
The spelling of 13403211144304 in words is "thirteen trillion, four hundred three billion, two hundred eleven million, one hundred forty-four thousand, three hundred four".
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