Base | Representation |
---|---|
bin | 11000111101110011… |
… | …00101000110111001 |
3 | 1021121002200211022001 |
4 | 30132321211012321 |
5 | 204422222000234 |
6 | 10053555301001 |
7 | 653101164013 |
oct | 143671450671 |
9 | 37532624261 |
10 | 13403312569 |
11 | 5758903129 |
12 | 27208aa761 |
13 | 1357b02caa |
14 | 9121531b3 |
15 | 536a6bd14 |
hex | 31ee651b9 |
13403312569 has 2 divisors, whose sum is σ = 13403312570. Its totient is φ = 13403312568.
The previous prime is 13403312477. The next prime is 13403312579. The reversal of 13403312569 is 96521330431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10831605625 + 2571706944 = 104075^2 + 50712^2 .
It is a cyclic number.
It is not a de Polignac number, because 13403312569 - 221 = 13401215417 is a prime.
It is a super-2 number, since 2×134033125692 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13403312579) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6701656284 + 6701656285.
It is an arithmetic number, because the mean of its divisors is an integer number (6701656285).
Almost surely, 213403312569 is an apocalyptic number.
It is an amenable number.
13403312569 is a deficient number, since it is larger than the sum of its proper divisors (1).
13403312569 is an equidigital number, since it uses as much as digits as its factorization.
13403312569 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 58320, while the sum is 37.
The spelling of 13403312569 in words is "thirteen billion, four hundred three million, three hundred twelve thousand, five hundred sixty-nine".
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