13403324622631 has 4 divisors (see below), whose sum is σ = 13409667892432. Its totient is φ = 13396981352832.

The previous prime is 13403324622587. The next prime is 13403324622719. The reversal of 13403324622631 is 13622642330431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13403324622631 - 2⁹ = 13403324622119 is a prime.

It is a super-2 number, since 2×13403324622631² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13403324629631) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3171631731 + ... + 3171635956.

It is an arithmetic number, because the mean of its divisors is an integer number (3352416973108).

Almost surely, 2^{13403324622631} is an apocalyptic number.

13403324622631 is a deficient number, since it is larger than the sum of its proper divisors (6343269801).

13403324622631 is an equidigital number, since it uses as much as digits as its factorization.

13403324622631 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6343269800.

The product of its (nonzero) digits is 373248, while the sum is 40.

The spelling of 13403324622631 in words is "thirteen trillion, four hundred three billion, three hundred twenty-four million, six hundred twenty-two thousand, six hundred thirty-one".