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13403334011012 = 2211497476123409
BaseRepresentation
bin1100001100001011010011…
…1101100110100010000100
31202110100100101121012120122
43003002310331212202010
53224100012001323022
644301223500121112
72552234053210211
oct303026475464204
952410311535518
1013403334011012
1142a835a6969a0
1216057a5536198
13762c0cc5662a
14344a20cd8b08
151839b8b00742
hexc30b4f66884

13403334011012 has 24 divisors (see below), whose sum is σ = 25588701657120. Its totient is φ = 6092301087360.

The previous prime is 13403334010981. The next prime is 13403334011027. The reversal of 13403334011012 is 21011043330431.

It is a super-2 number, since 2×134033340110122 (a number of 27 digits) contains 22 as substring.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 872837 + ... + 5250572.

It is an arithmetic number, because the mean of its divisors is an integer number (1066195902380).

Almost surely, 213403334011012 is an apocalyptic number.

It is an amenable number.

13403334011012 is a deficient number, since it is larger than the sum of its proper divisors (12185367646108).

13403334011012 is a wasteful number, since it uses less digits than its factorization.

13403334011012 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6173171 (or 6173169 counting only the distinct ones).

The product of its (nonzero) digits is 2592, while the sum is 26.

Adding to 13403334011012 its reverse (21011043330431), we get a palindrome (34414377341443).

The spelling of 13403334011012 in words is "thirteen trillion, four hundred three billion, three hundred thirty-four million, eleven thousand, twelve".

Divisors: 1 2 4 11 22 44 49747 99494 198988 547217 1094434 2188868 6123409 12246818 24493636 67357499 134714998 269429996 304621227523 609242455046 1218484910092 3350833502753 6701667005506 13403334011012