Base | Representation |
---|---|
bin | 11000111101110011… |
… | …11101111011101101 |
3 | 1021121002212222210010 |
4 | 30132321331323231 |
5 | 204422233224003 |
6 | 10054001403433 |
7 | 653102066325 |
oct | 143671757355 |
9 | 37532788703 |
10 | 13403414253 |
11 | 5758972569 |
12 | 2720939579 |
13 | 1357b3a368 |
14 | 91217c285 |
15 | 536a8c003 |
hex | 31ee7deed |
13403414253 has 8 divisors (see below), whose sum is σ = 18137953888. Its totient is φ = 8802242064.
The previous prime is 13403414251. The next prime is 13403414257. The reversal of 13403414253 is 35241430431.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 13403414253 - 21 = 13403414251 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is a self number, because there is not a number n which added to its sum of digits gives 13403414253.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13403414251) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 33341626 + ... + 33342027.
It is an arithmetic number, because the mean of its divisors is an integer number (2267244236).
Almost surely, 213403414253 is an apocalyptic number.
It is an amenable number.
13403414253 is a deficient number, since it is larger than the sum of its proper divisors (4734539635).
13403414253 is an equidigital number, since it uses as much as digits as its factorization.
13403414253 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 66683723.
The product of its (nonzero) digits is 17280, while the sum is 30.
Adding to 13403414253 its reverse (35241430431), we get a palindrome (48644844684).
The spelling of 13403414253 in words is "thirteen billion, four hundred three million, four hundred fourteen thousand, two hundred fifty-three".
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