Base | Representation |
---|---|
bin | 10011100000010010100… |
… | …111000010100011001111 |
3 | 11202010122201222102101021 |
4 | 103200102213002203033 |
5 | 133430010024122203 |
6 | 2503424501055011 |
7 | 165556632123046 |
oct | 23402247024317 |
9 | 4663581872337 |
10 | 1340342020303 |
11 | 477488145140 |
12 | 1979259b7467 |
13 | 99516c9aa80 |
14 | 48c3134755d |
15 | 24cea96b5bd |
hex | 138129c28cf |
1340342020303 has 16 divisors (see below), whose sum is σ = 1574706059136. Its totient is φ = 1124735027040.
The previous prime is 1340342020279. The next prime is 1340342020307. The reversal of 1340342020303 is 3030202430431.
It is a cyclic number.
It is not a de Polignac number, because 1340342020303 - 221 = 1340339923151 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1340342020307) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 7529200 + ... + 7705162.
It is an arithmetic number, because the mean of its divisors is an integer number (98419128696).
Almost surely, 21340342020303 is an apocalyptic number.
1340342020303 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
1340342020303 is a deficient number, since it is larger than the sum of its proper divisors (234364038833).
1340342020303 is a wasteful number, since it uses less digits than its factorization.
1340342020303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 229254.
The product of its (nonzero) digits is 5184, while the sum is 25.
Adding to 1340342020303 its reverse (3030202430431), we get a palindrome (4370544450734).
The spelling of 1340342020303 in words is "one trillion, three hundred forty billion, three hundred forty-two million, twenty thousand, three hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •