Base | Representation |
---|---|
bin | 11000111101110011… |
… | …11111111001011111 |
3 | 1021121002220101211021 |
4 | 30132321333321133 |
5 | 204422234003203 |
6 | 10054001505011 |
7 | 653102131645 |
oct | 143671777137 |
9 | 37532811737 |
10 | 13403422303 |
11 | 5758978617 |
12 | 2720942167 |
13 | 1357b40c1b |
14 | 912181195 |
15 | 536a8e5bd |
hex | 31ee7fe5f |
13403422303 has 4 divisors (see below), whose sum is σ = 13528688040. Its totient is φ = 13278156568.
The previous prime is 13403422297. The next prime is 13403422343. The reversal of 13403422303 is 30322430431.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30322430431 = 661 ⋅45873571.
It is a cyclic number.
It is not a de Polignac number, because 13403422303 - 25 = 13403422271 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13403422343) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 62632708 + ... + 62632921.
It is an arithmetic number, because the mean of its divisors is an integer number (3382172010).
Almost surely, 213403422303 is an apocalyptic number.
13403422303 is a deficient number, since it is larger than the sum of its proper divisors (125265737).
13403422303 is a wasteful number, since it uses less digits than its factorization.
13403422303 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 125265736.
The product of its (nonzero) digits is 5184, while the sum is 25.
Adding to 13403422303 its reverse (30322430431), we get a palindrome (43725852734).
The spelling of 13403422303 in words is "thirteen billion, four hundred three million, four hundred twenty-two thousand, three hundred three".
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