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1340343354111 = 34310390258559
BaseRepresentation
bin10011100000010010101…
…100001000001011111111
311202010122211111012000120
4103200102230020023333
5133430010344312421
62503424545430023
7165556646346516
oct23402254101377
94663584435016
101340343354111
11477488976263
1219792633b313
1399517346bc8
1448c315b367d
1524ceab318c6
hex13812b082ff

1340343354111 has 8 divisors (see below), whose sum is σ = 1828685506560. Its totient is φ = 872781718872.

The previous prime is 1340343354101. The next prime is 1340343354127. The reversal of 1340343354111 is 1114533430431.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1340343354111 - 27 = 1340343353983 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1340343354101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5195129151 + ... + 5195129408.

It is an arithmetic number, because the mean of its divisors is an integer number (228585688320).

Almost surely, 21340343354111 is an apocalyptic number.

1340343354111 is a deficient number, since it is larger than the sum of its proper divisors (488342152449).

1340343354111 is a wasteful number, since it uses less digits than its factorization.

1340343354111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10390258605.

The product of its (nonzero) digits is 25920, while the sum is 33.

Adding to 1340343354111 its reverse (1114533430431), we get a palindrome (2454876784542).

The spelling of 1340343354111 in words is "one trillion, three hundred forty billion, three hundred forty-three million, three hundred fifty-four thousand, one hundred eleven".

Divisors: 1 3 43 129 10390258559 31170775677 446781118037 1340343354111