Base | Representation |
---|---|
bin | 1100001100001101010010… |
… | …1110000111000111011011 |
3 | 1202110101201112011202120222 |
4 | 3003003110232013013123 |
5 | 3224102104401233313 |
6 | 44301352412110255 |
7 | 2552253213055304 |
oct | 303032456070733 |
9 | 52411645152528 |
10 | 13403866821083 |
11 | 42a8603422aa2 |
12 | 1605913a6538b |
13 | 762c9645876b |
14 | 344a719917ab |
15 | 1839ea79a208 |
hex | c30d4b871db |
13403866821083 has 4 divisors (see below), whose sum is σ = 13403879413368. Its totient is φ = 13403854228800.
The previous prime is 13403866821073. The next prime is 13403866821089. The reversal of 13403866821083 is 38012866830431.
It is a happy number.
13403866821083 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13403866821083 - 216 = 13403866755547 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13403866821089) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4535318 + ... + 6883083.
It is an arithmetic number, because the mean of its divisors is an integer number (3350969853342).
Almost surely, 213403866821083 is an apocalyptic number.
13403866821083 is a deficient number, since it is larger than the sum of its proper divisors (12592285).
13403866821083 is a wasteful number, since it uses less digits than its factorization.
13403866821083 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12592284.
The product of its (nonzero) digits is 3981312, while the sum is 53.
The spelling of 13403866821083 in words is "thirteen trillion, four hundred three billion, eight hundred sixty-six million, eight hundred twenty-one thousand, eighty-three".
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