1340400040123 has 2 divisors, whose sum is σ = 1340400040124. Its totient is φ = 1340400040122.

The previous prime is 1340400040097. The next prime is 1340400040129. The reversal of 1340400040123 is 3210400040431.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1340400040123 - 2²¹ = 1340397942971 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1340400040094 and 1340400040103.

It is not a weakly prime, because it can be changed into another prime (1340400040129) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670200020061 + 670200020062.

It is an arithmetic number, because the mean of its divisors is an integer number (670200020062).

Almost surely, 2^{1340400040123} is an apocalyptic number.

1340400040123 is a deficient number, since it is larger than the sum of its proper divisors (1).

1340400040123 is an equidigital number, since it uses as much as digits as its factorization.

1340400040123 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 22.

Adding to 1340400040123 its reverse (3210400040431), we get a palindrome (4550800080554).

The spelling of 1340400040123 in words is "one trillion, three hundred forty billion, four hundred million, forty thousand, one hundred twenty-three".