1340400040433 has 8 divisors (see below), whose sum is σ = 1373676869376. Its totient is φ = 1307151028000.

The previous prime is 1340400040423. The next prime is 1340400040457. The reversal of 1340400040433 is 3340400040431.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1340400040433 - 2²² = 1340395846129 is a prime.

It is a super-3 number, since 3×1340400040433³ (a number of 37 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1340400040423) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6856541 + ... + 7049322.

It is an arithmetic number, because the mean of its divisors is an integer number (171709608672).

Almost surely, 2^{1340400040433} is an apocalyptic number.

It is an amenable number.

1340400040433 is a deficient number, since it is larger than the sum of its proper divisors (33276828943).

1340400040433 is a wasteful number, since it uses less digits than its factorization.

1340400040433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13908255.

The product of its (nonzero) digits is 6912, while the sum is 26.

Adding to 1340400040433 its reverse (3340400040431), we get a palindrome (4680800080864).

The spelling of 1340400040433 in words is "one trillion, three hundred forty billion, four hundred million, forty thousand, four hundred thirty-three".