1340400040432 has 20 divisors (see below), whose sum is σ = 2604259142640. Its totient is φ = 668333164928.

The previous prime is 1340400040423. The next prime is 1340400040457. The reversal of 1340400040432 is 2340400040431.

It is a junction number, because it is equal to n+sod(n) for n = 1340400040397 and 1340400040406.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 116672533 + ... + 116684020.

It is an arithmetic number, because the mean of its divisors is an integer number (130212957132).

Almost surely, 2^{1340400040432} is an apocalyptic number.

It is an amenable number.

1340400040432 is a deficient number, since it is larger than the sum of its proper divisors (1263859102208).

1340400040432 is a wasteful number, since it uses less digits than its factorization.

1340400040432 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 233356920 (or 233356914 counting only the distinct ones).

The product of its (nonzero) digits is 4608, while the sum is 25.

Adding to 1340400040432 its reverse (2340400040431), we get a palindrome (3680800080863).

Subtracting 1340400040432 from its reverse (2340400040431), we obtain a palindrome (999999999999).

The spelling of 1340400040432 in words is "one trillion, three hundred forty billion, four hundred million, forty thousand, four hundred thirty-two".