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1340400040457 is a prime number
BaseRepresentation
bin10011100000010110000…
…100010111101000001001
311202010210210011011001212
4103200112010113220021
5133430114402243312
62503434332422505
7165561235233032
oct23402604275011
94663723134055
101340400040457
11477507973585
12197941317a35
139952600381a
1448c38d2ba89
1524d00acc822
hex13816117a09

1340400040457 has 2 divisors, whose sum is σ = 1340400040458. Its totient is φ = 1340400040456.

The previous prime is 1340400040423. The next prime is 1340400040489. The reversal of 1340400040457 is 7540400040431.

It is an a-pointer prime, because the next prime (1340400040489) can be obtained adding 1340400040457 to its sum of digits (32).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 833165502841 + 507234537616 = 912779^2 + 712204^2 .

It is a cyclic number.

It is not a de Polignac number, because 1340400040457 - 220 = 1340398991881 is a prime.

It is not a weakly prime, because it can be changed into another prime (1340400040657) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670200020228 + 670200020229.

It is an arithmetic number, because the mean of its divisors is an integer number (670200020229).

Almost surely, 21340400040457 is an apocalyptic number.

It is an amenable number.

1340400040457 is a deficient number, since it is larger than the sum of its proper divisors (1).

1340400040457 is an equidigital number, since it uses as much as digits as its factorization.

1340400040457 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 26880, while the sum is 32.

Adding to 1340400040457 its reverse (7540400040431), we get a palindrome (8880800080888).

The spelling of 1340400040457 in words is "one trillion, three hundred forty billion, four hundred million, forty thousand, four hundred fifty-seven".