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13404003221201 is a prime number
BaseRepresentation
bin1100001100001101110011…
…0110011011111011010001
31202110102002000211121101012
43003003130312123323101
53224102344311034301
644301414123420305
72552256460333265
oct303033466337321
952412060747335
1013404003221201
1142a867341646a
121605951684695
13762cb87a53a8
14344a85b3a0a5
15183a0773eebb
hexc30dcd9bed1

13404003221201 has 2 divisors, whose sum is σ = 13404003221202. Its totient is φ = 13404003221200.

The previous prime is 13404003221027. The next prime is 13404003221207. The reversal of 13404003221201 is 10212230040431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12232086553600 + 1171916667601 = 3497440^2 + 1082551^2 .

It is a cyclic number.

It is not a de Polignac number, because 13404003221201 - 214 = 13404003204817 is a prime.

It is not a weakly prime, because it can be changed into another prime (13404003221207) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6702001610600 + 6702001610601.

It is an arithmetic number, because the mean of its divisors is an integer number (6702001610601).

Almost surely, 213404003221201 is an apocalyptic number.

It is an amenable number.

13404003221201 is a deficient number, since it is larger than the sum of its proper divisors (1).

13404003221201 is an equidigital number, since it uses as much as digits as its factorization.

13404003221201 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 13404003221201 its reverse (10212230040431), we get a palindrome (23616233261632).

The spelling of 13404003221201 in words is "thirteen trillion, four hundred four billion, three million, two hundred twenty-one thousand, two hundred one".