1340400400301 has 4 divisors (see below), whose sum is σ = 1340461164672. Its totient is φ = 1340339635932.

The previous prime is 1340400400271. The next prime is 1340400400333. The reversal of 1340400400301 is 1030040040431.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1340400400301 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1340400403301) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 30349085 + ... + 30393218.

It is an arithmetic number, because the mean of its divisors is an integer number (335115291168).

Almost surely, 2^{1340400400301} is an apocalyptic number.

It is an amenable number.

1340400400301 is a deficient number, since it is larger than the sum of its proper divisors (60764371).

1340400400301 is an equidigital number, since it uses as much as digits as its factorization.

1340400400301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 60764370.

The product of its (nonzero) digits is 576, while the sum is 20.

Adding to 1340400400301 its reverse (1030040040431), we get a palindrome (2370440440732).

The spelling of 1340400400301 in words is "one trillion, three hundred forty billion, four hundred million, four hundred thousand, three hundred one".