1340404004003 has 2 divisors, whose sum is σ = 1340404004004. Its totient is φ = 1340404004002.

The previous prime is 1340404003957. The next prime is 1340404004033. The reversal of 1340404004003 is 3004004040431.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1340404004003 - 2¹⁴ = 1340403987619 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1340404004003.

It is not a weakly prime, because it can be changed into another prime (1340404004033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670202002001 + 670202002002.

It is an arithmetic number, because the mean of its divisors is an integer number (670202002002).

Almost surely, 2^{1340404004003} is an apocalyptic number.

1340404004003 is a deficient number, since it is larger than the sum of its proper divisors (1).

1340404004003 is an equidigital number, since it uses as much as digits as its factorization.

1340404004003 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2304, while the sum is 23.

Adding to 1340404004003 its reverse (3004004040431), we get a palindrome (4344408044434).

The spelling of 1340404004003 in words is "one trillion, three hundred forty billion, four hundred four million, four thousand, three".