13404044013 has 4 divisors (see below), whose sum is σ = 17872058688. Its totient is φ = 8936029340.

The previous prime is 13404043999. The next prime is 13404044039. The reversal of 13404044013 is 31044040431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13404044013 - 2⁶ = 13404043949 is a prime.

It is a super-2 number, since 2×13404044013² (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13404044713) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2234007333 + ... + 2234007338.

It is an arithmetic number, because the mean of its divisors is an integer number (4468014672).

Almost surely, 2^13404044013 is an apocalyptic number.

It is an amenable number.

13404044013 is a deficient number, since it is larger than the sum of its proper divisors (4468014675).

13404044013 is an equidigital number, since it uses as much as digits as its factorization.

13404044013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4468014674.

The product of its (nonzero) digits is 2304, while the sum is 24.

Adding to 13404044013 its reverse (31044040431), we get a palindrome (44448084444).

The spelling of 13404044013 in words is "thirteen billion, four hundred four million, forty-four thousand, thirteen".