Search a number
-
+
1340404523 is a prime number
BaseRepresentation
bin100111111100100…
…1111001100101011
310110102012121022222
41033321033030223
510221120421043
6341001304255
745134151623
oct11771171453
93412177288
101340404523
11628694837
12314a9508b
13184913993
14ca03b883
157ca21d68
hex4fe4f32b

1340404523 has 2 divisors, whose sum is σ = 1340404524. Its totient is φ = 1340404522.

The previous prime is 1340404489. The next prime is 1340404529. The reversal of 1340404523 is 3254040431.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1340404523 - 214 = 1340388139 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1340404492 and 1340404501.

It is not a weakly prime, because it can be changed into another prime (1340404529) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670202261 + 670202262.

It is an arithmetic number, because the mean of its divisors is an integer number (670202262).

Almost surely, 21340404523 is an apocalyptic number.

1340404523 is a deficient number, since it is larger than the sum of its proper divisors (1).

1340404523 is an equidigital number, since it uses as much as digits as its factorization.

1340404523 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5760, while the sum is 26.

The square root of 1340404523 is about 36611.5353816253. The cubic root of 1340404523 is about 1102.5846995909.

Adding to 1340404523 its reverse (3254040431), we get a palindrome (4594444954).

The spelling of 1340404523 in words is "one billion, three hundred forty million, four hundred four thousand, five hundred twenty-three".