13404061273 has 2 divisors, whose sum is σ = 13404061274. Its totient is φ = 13404061272.

The previous prime is 13404061241. The next prime is 13404061291. The reversal of 13404061273 is 37216040431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9456201049 + 3947860224 = 97243^2 + 62832^2 .

It is a cyclic number.

It is not a de Polignac number, because 13404061273 - 2⁵ = 13404061241 is a prime.

It is a super-2 number, since 2×13404061273² (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13404011273) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6702030636 + 6702030637.

It is an arithmetic number, because the mean of its divisors is an integer number (6702030637).

Almost surely, 2^13404061273 is an apocalyptic number.

It is an amenable number.

13404061273 is a deficient number, since it is larger than the sum of its proper divisors (1).

13404061273 is an equidigital number, since it uses as much as digits as its factorization.

13404061273 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12096, while the sum is 31.

The spelling of 13404061273 in words is "thirteen billion, four hundred four million, sixty-one thousand, two hundred seventy-three".