Base | Representation |
---|---|
bin | 10011100000010111011… |
… | …000010010111000001111 |
3 | 11202010212022112220021121 |
4 | 103200113120102320033 |
5 | 133430141020303403 |
6 | 2503440440141411 |
7 | 165561623233615 |
oct | 23402730227017 |
9 | 4663768486247 |
10 | 1340422041103 |
11 | 47751932aa32 |
12 | 197948767867 |
13 | 9952a737762 |
14 | 48c3bc176b5 |
15 | 24d029c63bd |
hex | 13817612e0f |
1340422041103 has 16 divisors (see below), whose sum is σ = 1425320069184. Its totient is φ = 1256197386240.
The previous prime is 1340422041073. The next prime is 1340422041131. The reversal of 1340422041103 is 3011402240431.
It is a cyclic number.
It is not a de Polignac number, because 1340422041103 - 217 = 1340421910031 is a prime.
It is a super-3 number, since 3×13404220411033 (a number of 37 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1340422041193) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 60981051 + ... + 61003027.
It is an arithmetic number, because the mean of its divisors is an integer number (89082504324).
Almost surely, 21340422041103 is an apocalyptic number.
1340422041103 is a deficient number, since it is larger than the sum of its proper divisors (84898028081).
1340422041103 is a wasteful number, since it uses less digits than its factorization.
1340422041103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 37122.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 1340422041103 its reverse (3011402240431), we get a palindrome (4351824281534).
The spelling of 1340422041103 in words is "one trillion, three hundred forty billion, four hundred twenty-two million, forty-one thousand, one hundred three".
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