Base | Representation |
---|---|
bin | 10011100000010111111… |
… | …011111111110111111101 |
3 | 11202010212222011101212220 |
4 | 103200113323333313331 |
5 | 133430200414303240 |
6 | 2503441412515553 |
7 | 165562065624414 |
oct | 23402773776775 |
9 | 4663788141786 |
10 | 1340431400445 |
11 | 477523642825 |
12 | 19794b91bbb9 |
13 | 9952c663827 |
14 | 48c3d17247b |
15 | 24d037245d0 |
hex | 13817effdfd |
1340431400445 has 32 divisors (see below), whose sum is σ = 2226105283584. Its totient is φ = 688013222400.
The previous prime is 1340431400437. The next prime is 1340431400491. The reversal of 1340431400445 is 5440041340431.
It is not a de Polignac number, because 1340431400445 - 23 = 1340431400437 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 7878952 + ... + 8047281.
It is an arithmetic number, because the mean of its divisors is an integer number (69565790112).
Almost surely, 21340431400445 is an apocalyptic number.
1340431400445 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
1340431400445 is a deficient number, since it is larger than the sum of its proper divisors (885673883139).
1340431400445 is a wasteful number, since it uses less digits than its factorization.
1340431400445 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 15926453.
The product of its (nonzero) digits is 46080, while the sum is 33.
Adding to 1340431400445 its reverse (5440041340431), we get a palindrome (6780472740876).
The spelling of 1340431400445 in words is "one trillion, three hundred forty billion, four hundred thirty-one million, four hundred thousand, four hundred forty-five".
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