Base | Representation |
---|---|
bin | 10011100000010111111… |
… | …100000010110010001011 |
3 | 11202010212222012000020022 |
4 | 103200113330002302023 |
5 | 133430200420143423 |
6 | 2503441413051055 |
7 | 165562066004231 |
oct | 23402774026213 |
9 | 4663788160208 |
10 | 1340431412363 |
11 | 47752365077a |
12 | 19794b926a8b |
13 | 9952c669094 |
14 | 48c3d176951 |
15 | 24d03727dc8 |
hex | 13817f02c8b |
1340431412363 has 2 divisors, whose sum is σ = 1340431412364. Its totient is φ = 1340431412362.
The previous prime is 1340431412227. The next prime is 1340431412381. The reversal of 1340431412363 is 3632141340431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1340431412363 - 234 = 1323251543179 is a prime.
It is not a weakly prime, because it can be changed into another prime (1340481412363) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670215706181 + 670215706182.
It is an arithmetic number, because the mean of its divisors is an integer number (670215706182).
Almost surely, 21340431412363 is an apocalyptic number.
1340431412363 is a deficient number, since it is larger than the sum of its proper divisors (1).
1340431412363 is an equidigital number, since it uses as much as digits as its factorization.
1340431412363 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 62208, while the sum is 35.
Adding to 1340431412363 its reverse (3632141340431), we get a palindrome (4972572752794).
The spelling of 1340431412363 in words is "one trillion, three hundred forty billion, four hundred thirty-one million, four hundred twelve thousand, three hundred sixty-three".
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