Base | Representation |
---|---|
bin | 111110011010110011… |
… | …0010010011001110001 |
3 | 110210222200221212120001 |
4 | 1330311212102121301 |
5 | 4144010030343343 |
6 | 141324551150001 |
7 | 12453500350366 |
oct | 1746546223161 |
9 | 423880855501 |
10 | 134043215473 |
11 | 5193599a822 |
12 | 21b8a975301 |
13 | c84274751b |
14 | 66b846c46d |
15 | 3747cc344d |
hex | 1f35992671 |
134043215473 has 2 divisors, whose sum is σ = 134043215474. Its totient is φ = 134043215472.
The previous prime is 134043215419. The next prime is 134043215489. The reversal of 134043215473 is 374512340431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 102056608369 + 31986607104 = 319463^2 + 178848^2 .
It is a cyclic number.
It is not a de Polignac number, because 134043215473 - 29 = 134043214961 is a prime.
It is a super-2 number, since 2×1340432154732 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (134043215413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67021607736 + 67021607737.
It is an arithmetic number, because the mean of its divisors is an integer number (67021607737).
Almost surely, 2134043215473 is an apocalyptic number.
It is an amenable number.
134043215473 is a deficient number, since it is larger than the sum of its proper divisors (1).
134043215473 is an equidigital number, since it uses as much as digits as its factorization.
134043215473 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 120960, while the sum is 37.
The spelling of 134043215473 in words is "one hundred thirty-four billion, forty-three million, two hundred fifteen thousand, four hundred seventy-three".
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