Base | Representation |
---|---|
bin | 10011100000010111111… |
… | …111110110100110000011 |
3 | 11202010220001001202010021 |
4 | 103200113333312212003 |
5 | 133430201144123021 |
6 | 2503441450314311 |
7 | 165562110333601 |
oct | 23402777664603 |
9 | 4663801052107 |
10 | 1340432411011 |
11 | 477524173001 |
12 | 197950128997 |
13 | 9952c9287b5 |
14 | 48c3d356871 |
15 | 24d03873c41 |
hex | 13817ff6983 |
1340432411011 has 4 divisors (see below), whose sum is σ = 1350664719624. Its totient is φ = 1330200102400.
The previous prime is 1340432410979. The next prime is 1340432411039. The reversal of 1340432411011 is 1101142340431.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1340432411011 - 25 = 1340432410979 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1340432711011) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5116154110 + ... + 5116154371.
It is an arithmetic number, because the mean of its divisors is an integer number (337666179906).
Almost surely, 21340432411011 is an apocalyptic number.
1340432411011 is a deficient number, since it is larger than the sum of its proper divisors (10232308613).
1340432411011 is a wasteful number, since it uses less digits than its factorization.
1340432411011 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10232308612.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 1340432411011 its reverse (1101142340431), we get a palindrome (2441574751442).
The spelling of 1340432411011 in words is "one trillion, three hundred forty billion, four hundred thirty-two million, four hundred eleven thousand, eleven".
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