Base | Representation |
---|---|
bin | 100111111100101… |
… | …0110001100100011 |
3 | 10110102021001122121 |
4 | 1033321112030203 |
5 | 10221122330222 |
6 | 341002045111 |
7 | 45134331322 |
oct | 11771261443 |
9 | 3412231577 |
10 | 1340433187 |
11 | 628704325 |
12 | 314aa9797 |
13 | 184923a42 |
14 | ca0480b9 |
15 | 7ca2a5c7 |
hex | 4fe56323 |
1340433187 has 16 divisors (see below), whose sum is σ = 1434399840. Its totient is φ = 1248219648.
The previous prime is 1340433181. The next prime is 1340433197. The reversal of 1340433187 is 7813340431.
It is a cyclic number.
It is not a de Polignac number, because 1340433187 - 223 = 1332044579 is a prime.
It is a super-2 number, since 2×13404331872 = 3593522257621953938, which contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1340433181) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 717028 + ... + 718894.
It is an arithmetic number, because the mean of its divisors is an integer number (89649990).
Almost surely, 21340433187 is an apocalyptic number.
1340433187 is a gapful number since it is divisible by the number (17) formed by its first and last digit.
1340433187 is a deficient number, since it is larger than the sum of its proper divisors (93966653).
1340433187 is a wasteful number, since it uses less digits than its factorization.
1340433187 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2310.
The product of its (nonzero) digits is 24192, while the sum is 34.
The square root of 1340433187 is about 36611.9268408534. The cubic root of 1340433187 is about 1102.5925589751.
The spelling of 1340433187 in words is "one billion, three hundred forty million, four hundred thirty-three thousand, one hundred eighty-seven".
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