1340433313001 has 2 divisors, whose sum is σ = 1340433313002. Its totient is φ = 1340433313000.

The previous prime is 1340433312997. The next prime is 1340433313057. The reversal of 1340433313001 is 1003133340431.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 882613275625 + 457820037376 = 939475^2 + 676624^2 .

It is a cyclic number.

It is not a de Polignac number, because 1340433313001 - 2² = 1340433312997 is a prime.

It is a super-2 number, since 2×1340433313001² (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1340436313001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670216656500 + 670216656501.

It is an arithmetic number, because the mean of its divisors is an integer number (670216656501).

Almost surely, 2^{1340433313001} is an apocalyptic number.

It is an amenable number.

1340433313001 is a deficient number, since it is larger than the sum of its proper divisors (1).

1340433313001 is an equidigital number, since it uses as much as digits as its factorization.

1340433313001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3888, while the sum is 26.

Adding to 1340433313001 its reverse (1003133340431), we get a palindrome (2343566653432).

The spelling of 1340433313001 in words is "one trillion, three hundred forty billion, four hundred thirty-three million, three hundred thirteen thousand, one".