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13404431413 = 79169676347
BaseRepresentation
bin11000111101111011…
…10110010000110101
31021121011210200001201
430132331312100311
5204423013301123
610054035252501
7653113533652
oct143675662065
937534720051
1013404431413
1157594a779a
12272114a131
131358105329
14912364c29
15536bdd5ad
hex31ef76435

13404431413 has 4 divisors (see below), whose sum is σ = 13574107840. Its totient is φ = 13234754988.

The previous prime is 13404431389. The next prime is 13404431483. The reversal of 13404431413 is 31413440431.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13404431413 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13404431483) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 84838095 + ... + 84838252.

It is an arithmetic number, because the mean of its divisors is an integer number (3393526960).

Almost surely, 213404431413 is an apocalyptic number.

It is an amenable number.

13404431413 is a deficient number, since it is larger than the sum of its proper divisors (169676427).

13404431413 is an equidigital number, since it uses as much as digits as its factorization.

13404431413 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 169676426.

The product of its (nonzero) digits is 6912, while the sum is 28.

Adding to 13404431413 its reverse (31413440431), we get a palindrome (44817871844).

It can be divided in two parts, 1340 and 4431413, that added together give a triangular number (4432753 = T2977).

The spelling of 13404431413 in words is "thirteen billion, four hundred four million, four hundred thirty-one thousand, four hundred thirteen".

Divisors: 1 79 169676347 13404431413