Base | Representation |
---|---|
bin | 111110011010110110… |
… | …1100110011110110011 |
3 | 110210222211120021112022 |
4 | 1330311231212132303 |
5 | 4144011023221343 |
6 | 141325100222055 |
7 | 12453522554135 |
oct | 1746555463663 |
9 | 423884507468 |
10 | 134045132723 |
11 | 51936a8a227 |
12 | 21b8b53a92b |
13 | c842c690a8 |
14 | 66b880b055 |
15 | 3748051568 |
hex | 1f35b667b3 |
134045132723 has 2 divisors, whose sum is σ = 134045132724. Its totient is φ = 134045132722.
The previous prime is 134045132701. The next prime is 134045132729. The reversal of 134045132723 is 327231540431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 134045132723 - 212 = 134045128627 is a prime.
It is not a weakly prime, because it can be changed into another prime (134045132729) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67022566361 + 67022566362.
It is an arithmetic number, because the mean of its divisors is an integer number (67022566362).
Almost surely, 2134045132723 is an apocalyptic number.
134045132723 is a deficient number, since it is larger than the sum of its proper divisors (1).
134045132723 is an equidigital number, since it uses as much as digits as its factorization.
134045132723 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 60480, while the sum is 35.
The spelling of 134045132723 in words is "one hundred thirty-four billion, forty-five million, one hundred thirty-two thousand, seven hundred twenty-three".
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