1340452533421 has 4 divisors (see below), whose sum is σ = 1347188476000. Its totient is φ = 1333716590844.

The previous prime is 1340452533419. The next prime is 1340452533461. The reversal of 1340452533421 is 1243352540431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1340452533421 - 2¹ = 1340452533419 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1340452533401) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3367970991 + ... + 3367971388.

It is an arithmetic number, because the mean of its divisors is an integer number (336797119000).

Almost surely, 2^{1340452533421} is an apocalyptic number.

It is an amenable number.

1340452533421 is a deficient number, since it is larger than the sum of its proper divisors (6735942579).

1340452533421 is an equidigital number, since it uses as much as digits as its factorization.

1340452533421 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6735942578.

The product of its (nonzero) digits is 172800, while the sum is 37.

The spelling of 1340452533421 in words is "one trillion, three hundred forty billion, four hundred fifty-two million, five hundred thirty-three thousand, four hundred twenty-one".