Base | Representation |
---|---|
bin | 111110011010111011… |
… | …0011111000010101011 |
3 | 110210222222221121002001 |
4 | 1330311312133002223 |
5 | 4144012122232142 |
6 | 141325222151431 |
7 | 12453551423536 |
oct | 1746566370253 |
9 | 423888847061 |
10 | 134047461547 |
11 | 5193832a97a |
12 | 21b90282577 |
13 | c8435a30ac |
14 | 66b8c55a1d |
15 | 37483615b7 |
hex | 1f35d9f0ab |
134047461547 has 2 divisors, whose sum is σ = 134047461548. Its totient is φ = 134047461546.
The previous prime is 134047461419. The next prime is 134047461551. The reversal of 134047461547 is 745164740431.
It is a strong prime.
It is an emirp because it is prime and its reverse (745164740431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 134047461547 - 27 = 134047461419 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 134047461497 and 134047461506.
It is not a weakly prime, because it can be changed into another prime (134045461547) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67023730773 + 67023730774.
It is an arithmetic number, because the mean of its divisors is an integer number (67023730774).
Almost surely, 2134047461547 is an apocalyptic number.
134047461547 is a deficient number, since it is larger than the sum of its proper divisors (1).
134047461547 is an equidigital number, since it uses as much as digits as its factorization.
134047461547 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1128960, while the sum is 46.
The spelling of 134047461547 in words is "one hundred thirty-four billion, forty-seven million, four hundred sixty-one thousand, five hundred forty-seven".
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