Base | Representation |
---|---|
bin | 111110011010111011… |
… | …0100001100000110011 |
3 | 110210222222222002221212 |
4 | 1330311312201200303 |
5 | 4144012123043132 |
6 | 141325222310335 |
7 | 12453551465204 |
oct | 1746566414063 |
9 | 423888862855 |
10 | 134047471667 |
11 | 5193833753a |
12 | 21b902883ab |
13 | c8435a7895 |
14 | 66b8c595ab |
15 | 37483645b2 |
hex | 1f35da1833 |
134047471667 has 2 divisors, whose sum is σ = 134047471668. Its totient is φ = 134047471666.
The previous prime is 134047471651. The next prime is 134047471673. The reversal of 134047471667 is 766174740431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 134047471667 - 24 = 134047471651 is a prime.
It is not a weakly prime, because it can be changed into another prime (134047471627) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67023735833 + 67023735834.
It is an arithmetic number, because the mean of its divisors is an integer number (67023735834).
Almost surely, 2134047471667 is an apocalyptic number.
134047471667 is a deficient number, since it is larger than the sum of its proper divisors (1).
134047471667 is an equidigital number, since it uses as much as digits as its factorization.
134047471667 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2370816, while the sum is 50.
It can be divided in two parts, 1340474 and 71667, that added together give a palindrome (1412141).
The spelling of 134047471667 in words is "one hundred thirty-four billion, forty-seven million, four hundred seventy-one thousand, six hundred sixty-seven".
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