Base | Representation |
---|---|
bin | 111110011011000000… |
… | …1010100001010010001 |
3 | 110211000012021211110201 |
4 | 1330312001110022101 |
5 | 4144013334104221 |
6 | 141325403055201 |
7 | 12453614516542 |
oct | 1746601241221 |
9 | 424005254421 |
10 | 134050300561 |
11 | 51939999971 |
12 | 21b91211501 |
13 | c844058398 |
14 | 66b93944c9 |
15 | 3748722891 |
hex | 1f36054291 |
134050300561 has 2 divisors, whose sum is σ = 134050300562. Its totient is φ = 134050300560.
The previous prime is 134050300511. The next prime is 134050300577. The reversal of 134050300561 is 165003050431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 115083777600 + 18966522961 = 339240^2 + 137719^2 .
It is an emirp because it is prime and its reverse (165003050431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 134050300561 - 229 = 133513429649 is a prime.
It is not a weakly prime, because it can be changed into another prime (134050300511) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67025150280 + 67025150281.
It is an arithmetic number, because the mean of its divisors is an integer number (67025150281).
Almost surely, 2134050300561 is an apocalyptic number.
It is an amenable number.
134050300561 is a deficient number, since it is larger than the sum of its proper divisors (1).
134050300561 is an equidigital number, since it uses as much as digits as its factorization.
134050300561 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5400, while the sum is 28.
Adding to 134050300561 its reverse (165003050431), we get a palindrome (299053350992).
The spelling of 134050300561 in words is "one hundred thirty-four billion, fifty million, three hundred thousand, five hundred sixty-one".
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