Base | Representation |
---|---|
bin | 111110011011000001… |
… | …0001010000100111011 |
3 | 110211000012201001102001 |
4 | 1330312002022010323 |
5 | 4144013413141103 |
6 | 141325411521431 |
7 | 12453616426441 |
oct | 1746602120473 |
9 | 424005631361 |
10 | 134050521403 |
11 | 5193a02a887 |
12 | 21b912b9277 |
13 | c844104a66 |
14 | 66b9410b91 |
15 | 374876801d |
hex | 1f3608a13b |
134050521403 has 2 divisors, whose sum is σ = 134050521404. Its totient is φ = 134050521402.
The previous prime is 134050521349. The next prime is 134050521427. The reversal of 134050521403 is 304125050431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 134050521403 - 225 = 134016966971 is a prime.
It is a super-2 number, since 2×1340505214032 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (134050521463) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67025260701 + 67025260702.
It is an arithmetic number, because the mean of its divisors is an integer number (67025260702).
Almost surely, 2134050521403 is an apocalyptic number.
134050521403 is a deficient number, since it is larger than the sum of its proper divisors (1).
134050521403 is an equidigital number, since it uses as much as digits as its factorization.
134050521403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7200, while the sum is 28.
Adding to 134050521403 its reverse (304125050431), we get a palindrome (438175571834).
The spelling of 134050521403 in words is "one hundred thirty-four billion, fifty million, five hundred twenty-one thousand, four hundred three".
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