13405243431335 has 32 divisors (see below), whose sum is σ = 20490279229440. Its totient is φ = 8196111677952.

The previous prime is 13405243431317. The next prime is 13405243431397. The reversal of 13405243431335 is 53313434250431.

13405243431335 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a cyclic number.

It is not a de Polignac number, because 13405243431335 - 2²⁸ = 13404974995879 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13405243431292 and 13405243431301.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 592878719 + ... + 592901328.

It is an arithmetic number, because the mean of its divisors is an integer number (640321225920).

Almost surely, 2^{13405243431335} is an apocalyptic number.

13405243431335 is a deficient number, since it is larger than the sum of its proper divisors (7085035798105).

13405243431335 is a wasteful number, since it uses less digits than its factorization.

13405243431335 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1185780095.

The product of its (nonzero) digits is 777600, while the sum is 41.

Adding to 13405243431335 its reverse (53313434250431), we get a palindrome (66718677681766).

The spelling of 13405243431335 in words is "thirteen trillion, four hundred five billion, two hundred forty-three million, four hundred thirty-one thousand, three hundred thirty-five".