Base | Representation |
---|---|
bin | 11000111110000010… |
… | …10110100011010001 |
3 | 1021121020112100021001 |
4 | 30133001112203101 |
5 | 204423232200342 |
6 | 10054111102001 |
7 | 653124411226 |
oct | 143701264321 |
9 | 37536470231 |
10 | 13405350097 |
11 | 5759a74a37 |
12 | 2721511901 |
13 | 1358367529 |
14 | 91252394d |
15 | 536d208b7 |
hex | 31f0568d1 |
13405350097 has 2 divisors, whose sum is σ = 13405350098. Its totient is φ = 13405350096.
The previous prime is 13405350073. The next prime is 13405350149. The reversal of 13405350097 is 79005350431.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 13182713856 + 222636241 = 114816^2 + 14921^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13405350097 is a prime.
It is a super-2 number, since 2×134053500972 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13405350047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6702675048 + 6702675049.
It is an arithmetic number, because the mean of its divisors is an integer number (6702675049).
Almost surely, 213405350097 is an apocalyptic number.
It is an amenable number.
13405350097 is a deficient number, since it is larger than the sum of its proper divisors (1).
13405350097 is an equidigital number, since it uses as much as digits as its factorization.
13405350097 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 56700, while the sum is 37.
The spelling of 13405350097 in words is "thirteen billion, four hundred five million, three hundred fifty thousand, ninety-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •