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13405423104044 = 223351355776011
BaseRepresentation
bin1100001100010011000101…
…1110110111000000101100
31202110112201222121010110122
43003010301132313000230
53224113301303312134
644302211044424112
72552336611206356
oct303046136670054
952415658533418
1013405423104044
1142a9231955464
1216060890a8038
137631839c5b5a
14344b7c5460d6
15183a8c21102e
hexc31317b702c

13405423104044 has 6 divisors (see below), whose sum is σ = 23459490432084. Its totient is φ = 6702711552020.

The previous prime is 13405423104013. The next prime is 13405423104077. The reversal of 13405423104044 is 44040132450431.

It is a happy number.

It is a junction number, because it is equal to n+sod(n) for n = 13405423103995 and 13405423104013.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1675677888002 + ... + 1675677888009.

It is an arithmetic number, because the mean of its divisors is an integer number (3909915072014).

Almost surely, 213405423104044 is an apocalyptic number.

It is an amenable number.

13405423104044 is a deficient number, since it is larger than the sum of its proper divisors (10054067328040).

13405423104044 is a wasteful number, since it uses less digits than its factorization.

13405423104044 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3351355776015 (or 3351355776013 counting only the distinct ones).

The product of its (nonzero) digits is 92160, while the sum is 35.

Adding to 13405423104044 its reverse (44040132450431), we get a palindrome (57445555554475).

The spelling of 13405423104044 in words is "thirteen trillion, four hundred five billion, four hundred twenty-three million, one hundred four thousand, forty-four".

Divisors: 1 2 4 3351355776011 6702711552022 13405423104044