Base | Representation |
---|---|
bin | 1100001100010011000110… |
… | …0011000101100110000011 |
3 | 1202110112202001200102210012 |
4 | 3003010301203011212003 |
5 | 3224113302044243410 |
6 | 44302211124255135 |
7 | 2552336623503530 |
oct | 303046143054603 |
9 | 52415661612705 |
10 | 13405424212355 |
11 | 42a923254211a |
12 | 16060895414ab |
13 | 763183cc3466 |
14 | 344b7c753d87 |
15 | 183a8c37e605 |
hex | c31318c5983 |
13405424212355 has 16 divisors (see below), whose sum is σ = 18832986212544. Its totient is φ = 8968088670720.
The previous prime is 13405424212343. The next prime is 13405424212357. The reversal of 13405424212355 is 55321242450431.
It is not a de Polignac number, because 13405424212355 - 28 = 13405424212099 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (41).
It is not an unprimeable number, because it can be changed into a prime (13405424212357) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4670878082 + ... + 4670880951.
It is an arithmetic number, because the mean of its divisors is an integer number (1177061638284).
Almost surely, 213405424212355 is an apocalyptic number.
13405424212355 is a deficient number, since it is larger than the sum of its proper divisors (5427562000189).
13405424212355 is an equidigital number, since it uses as much as digits as its factorization.
13405424212355 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9341759086.
The product of its (nonzero) digits is 576000, while the sum is 41.
Adding to 13405424212355 its reverse (55321242450431), we get a palindrome (68726666662786).
The spelling of 13405424212355 in words is "thirteen trillion, four hundred five billion, four hundred twenty-four million, two hundred twelve thousand, three hundred fifty-five".
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