Base | Representation |
---|---|
bin | 1100001100010011000110… |
… | …0011000101100010000011 |
3 | 1202110112202001200102102201 |
4 | 3003010301203011202003 |
5 | 3224113302044241344 |
6 | 44302211124254031 |
7 | 2552336623503013 |
oct | 303046143054203 |
9 | 52415661612381 |
10 | 13405424212099 |
11 | 42a9232541a07 |
12 | 1606089541317 |
13 | 763183cc32ca |
14 | 344b7c753c43 |
15 | 183a8c37e4d4 |
hex | c31318c5883 |
13405424212099 has 2 divisors, whose sum is σ = 13405424212100. Its totient is φ = 13405424212098.
The previous prime is 13405424212067. The next prime is 13405424212111. The reversal of 13405424212099 is 99021242450431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13405424212099 - 25 = 13405424212067 is a prime.
It is not a weakly prime, because it can be changed into another prime (13405424512099) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6702712106049 + 6702712106050.
It is an arithmetic number, because the mean of its divisors is an integer number (6702712106050).
Almost surely, 213405424212099 is an apocalyptic number.
13405424212099 is a deficient number, since it is larger than the sum of its proper divisors (1).
13405424212099 is an equidigital number, since it uses as much as digits as its factorization.
13405424212099 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 622080, while the sum is 46.
The spelling of 13405424212099 in words is "thirteen trillion, four hundred five billion, four hundred twenty-four million, two hundred twelve thousand, ninety-nine".
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