Base | Representation |
---|---|
bin | 1100001100010011000110… |
… | …0011000101100101110111 |
3 | 1202110112202001200102202202 |
4 | 3003010301203011211313 |
5 | 3224113302044243333 |
6 | 44302211124255115 |
7 | 2552336623503512 |
oct | 303046143054567 |
9 | 52415661612682 |
10 | 13405424212343 |
11 | 42a9232542109 |
12 | 160608954149b |
13 | 763183cc3457 |
14 | 344b7c753d79 |
15 | 183a8c37e5e8 |
hex | c31318c5977 |
13405424212343 has 2 divisors, whose sum is σ = 13405424212344. Its totient is φ = 13405424212342.
The previous prime is 13405424212319. The next prime is 13405424212357. The reversal of 13405424212343 is 34321242450431.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13405424212343 - 218 = 13405423950199 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13405424212297 and 13405424212306.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13405424212373) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6702712106171 + 6702712106172.
It is an arithmetic number, because the mean of its divisors is an integer number (6702712106172).
Almost surely, 213405424212343 is an apocalyptic number.
13405424212343 is a deficient number, since it is larger than the sum of its proper divisors (1).
13405424212343 is an equidigital number, since it uses as much as digits as its factorization.
13405424212343 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 276480, while the sum is 38.
Adding to 13405424212343 its reverse (34321242450431), we get a palindrome (47726666662774).
The spelling of 13405424212343 in words is "thirteen trillion, four hundred five billion, four hundred twenty-four million, two hundred twelve thousand, three hundred forty-three".
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