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13405424502400 = 275272417247603
BaseRepresentation
bin1100001100010011000110…
…0100001100011010000000
31202110112202002020011122121
43003010301210030122000
53224113302133034100
644302211134414024
72552336626122250
oct303046144143200
952415662204577
1013405424502400
1142a9232720027
121606089661314
13763184095498
14344b7c7cb960
15183a8c3da51a
hexc313190c680

13405424502400 has 192 divisors, whose sum is σ = 37862197289280. Its totient is φ = 4594225397760.

The previous prime is 13405424502391. The next prime is 13405424502413. The reversal of 13405424502400 is 420542450431.

It is an unprimeable number.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 54016999 + ... + 54264601.

It is an arithmetic number, because the mean of its divisors is an integer number (197198944215).

Almost surely, 213405424502400 is an apocalyptic number.

13405424502400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13405424502400, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (18931098644640).

13405424502400 is an abundant number, since it is smaller than the sum of its proper divisors (24456772786880).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13405424502400 is a wasteful number, since it uses less digits than its factorization.

13405424502400 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 250051 (or 250034 counting only the distinct ones).

The product of its (nonzero) digits is 76800, while the sum is 34.

Adding to 13405424502400 its reverse (420542450431), we get a palindrome (13825966952831).

The spelling of 13405424502400 in words is "thirteen trillion, four hundred five billion, four hundred twenty-four million, five hundred two thousand, four hundred".