Base | Representation |
---|---|
bin | 1100001100010011000111… |
… | …1011001110011101000101 |
3 | 1202110112202111120220211011 |
4 | 3003010301323032131011 |
5 | 3224113310204240401 |
6 | 44302211512042221 |
7 | 2552340031340005 |
oct | 303046173163505 |
9 | 52415674526734 |
10 | 13405430540101 |
11 | 42a9236074266 |
12 | 160608b693371 |
13 | 7631853ca6a2 |
14 | 344b7d520005 |
15 | 183a8cbce451 |
hex | c3131ece745 |
13405430540101 has 16 divisors (see below), whose sum is σ = 14524573174848. Its totient is φ = 12323039904000.
The previous prime is 13405430540081. The next prime is 13405430540113. The reversal of 13405430540101 is 10104503450431.
13405430540101 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 13405430540101 - 215 = 13405430507333 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13405430540701) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 22254871 + ... + 22849291.
It is an arithmetic number, because the mean of its divisors is an integer number (907785823428).
Almost surely, 213405430540101 is an apocalyptic number.
It is an amenable number.
13405430540101 is a deficient number, since it is larger than the sum of its proper divisors (1119142634747).
13405430540101 is a wasteful number, since it uses less digits than its factorization.
13405430540101 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 625332.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 13405430540101 its reverse (10104503450431), we get a palindrome (23509933990532).
The spelling of 13405430540101 in words is "thirteen trillion, four hundred five billion, four hundred thirty million, five hundred forty thousand, one hundred one".
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