13405430540113 has 2 divisors, whose sum is σ = 13405430540114. Its totient is φ = 13405430540112.

The previous prime is 13405430540081. The next prime is 13405430540179. The reversal of 13405430540113 is 31104503450431.

13405430540113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9127842797824 + 4277587742289 = 3021232^2 + 2068233^2 .

It is a cyclic number.

It is not a de Polignac number, because 13405430540113 - 2⁵ = 13405430540081 is a prime.

It is not a weakly prime, because it can be changed into another prime (13405430940113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6702715270056 + 6702715270057.

It is an arithmetic number, because the mean of its divisors is an integer number (6702715270057).

Almost surely, 2^{13405430540113} is an apocalyptic number.

It is an amenable number.

13405430540113 is a deficient number, since it is larger than the sum of its proper divisors (1).

13405430540113 is an equidigital number, since it uses as much as digits as its factorization.

13405430540113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 43200, while the sum is 34.

Adding to 13405430540113 its reverse (31104503450431), we get a palindrome (44509933990544).

The spelling of 13405430540113 in words is "thirteen trillion, four hundred five billion, four hundred thirty million, five hundred forty thousand, one hundred thirteen".