Base | Representation |
---|---|
bin | 1100001100010011011001… |
… | …0100010001000110111000 |
3 | 1202110112221122012220122001 |
4 | 3003010312110101012320 |
5 | 3224113433034312212 |
6 | 44302223103110344 |
7 | 2552341614503032 |
oct | 303046624210670 |
9 | 52415848186561 |
10 | 13405504213432 |
11 | 42a9273714111 |
12 | 16060b02a23b4 |
13 | 763197754186 |
14 | 344b8921ac52 |
15 | 183a943d3657 |
hex | c31365111b8 |
13405504213432 has 48 divisors (see below), whose sum is σ = 25414799913360. Its totient is φ = 6628409922816.
The previous prime is 13405504213393. The next prime is 13405504213433. The reversal of 13405504213432 is 23431240550431.
It is a junction number, because it is equal to n+sod(n) for n = 13405504213391 and 13405504213400.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13405504213433) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 3076771798 + ... + 3076776154.
It is an arithmetic number, because the mean of its divisors is an integer number (529474998195).
Almost surely, 213405504213432 is an apocalyptic number.
It is an amenable number.
13405504213432 is a deficient number, since it is larger than the sum of its proper divisors (12009295699928).
13405504213432 is an frugal number, since it uses more digits than its factorization.
13405504213432 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9680 (or 5319 counting only the distinct ones).
The product of its (nonzero) digits is 172800, while the sum is 37.
Adding to 13405504213432 its reverse (23431240550431), we get a palindrome (36836744763863).
The spelling of 13405504213432 in words is "thirteen trillion, four hundred five billion, five hundred four million, two hundred thirteen thousand, four hundred thirty-two".
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