13405504213503 has 12 divisors (see below), whose sum is σ = 19504845548448. Its totient is φ = 8871769211040.

The previous prime is 13405504213501. The next prime is 13405504213513. The reversal of 13405504213503 is 30531240550431.

13405504213503 is a `hidden beast` number, since 1 + 3 + 4 + 0 + 550 + 42 + 13 + 50 + 3 = 666.

13405504213503 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 13405504213503 - 2¹ = 13405504213501 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13405504213501) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 5436131863 + ... + 5436134328.

It is an arithmetic number, because the mean of its divisors is an integer number (1625403795704).

Almost surely, 2^{13405504213503} is an apocalyptic number.

13405504213503 is a deficient number, since it is larger than the sum of its proper divisors (6099341334945).

13405504213503 is a wasteful number, since it uses less digits than its factorization.

13405504213503 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10872266334 (or 10872266331 counting only the distinct ones).

The product of its (nonzero) digits is 108000, while the sum is 36.

Adding to 13405504213503 its reverse (30531240550431), we get a palindrome (43936744763934).

The spelling of 13405504213503 in words is "thirteen trillion, four hundred five billion, five hundred four million, two hundred thirteen thousand, five hundred three".