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13405504213501 is a prime number
BaseRepresentation
bin1100001100010011011001…
…0100010001000111111101
31202110112221122012220201121
43003010312110101013331
53224113433034313001
644302223103110541
72552341614503161
oct303046624210775
952415848186647
1013405504213501
1142a9273714174
1216060b02a2451
1376319775420a
14344b8921aca1
15183a943d36a1
hexc31365111fd

13405504213501 has 2 divisors, whose sum is σ = 13405504213502. Its totient is φ = 13405504213500.

The previous prime is 13405504213457. The next prime is 13405504213513. The reversal of 13405504213501 is 10531240550431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13315741057476 + 89763156025 = 3649074^2 + 299605^2 .

It is an emirp because it is prime and its reverse (10531240550431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13405504213501 - 217 = 13405504082429 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13405504213531) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6702752106750 + 6702752106751.

It is an arithmetic number, because the mean of its divisors is an integer number (6702752106751).

Almost surely, 213405504213501 is an apocalyptic number.

It is an amenable number.

13405504213501 is a deficient number, since it is larger than the sum of its proper divisors (1).

13405504213501 is an equidigital number, since it uses as much as digits as its factorization.

13405504213501 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 36000, while the sum is 34.

Adding to 13405504213501 its reverse (10531240550431), we get a palindrome (23936744763932).

The spelling of 13405504213501 in words is "thirteen trillion, four hundred five billion, five hundred four million, two hundred thirteen thousand, five hundred one".