Base | Representation |
---|---|
bin | 111110011011001010… |
… | …0001100110110000001 |
3 | 110211000112121100122111 |
4 | 1330312110030312001 |
5 | 4144021121020304 |
6 | 141330101135321 |
7 | 12454004556346 |
oct | 1746624146601 |
9 | 424015540574 |
10 | 134055251329 |
11 | 5194177050a |
12 | 21b929ba541 |
13 | c84509c92c |
14 | 66b9cc27cd |
15 | 3748d9e704 |
hex | 1f3650cd81 |
134055251329 has 2 divisors, whose sum is σ = 134055251330. Its totient is φ = 134055251328.
The previous prime is 134055251261. The next prime is 134055251333. The reversal of 134055251329 is 923152550431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 101735481600 + 32319769729 = 318960^2 + 179777^2 .
It is an emirp because it is prime and its reverse (923152550431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 134055251329 - 211 = 134055249281 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 134055251291 and 134055251300.
It is not a weakly prime, because it can be changed into another prime (134055251339) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67027625664 + 67027625665.
It is an arithmetic number, because the mean of its divisors is an integer number (67027625665).
Almost surely, 2134055251329 is an apocalyptic number.
It is an amenable number.
134055251329 is a deficient number, since it is larger than the sum of its proper divisors (1).
134055251329 is an equidigital number, since it uses as much as digits as its factorization.
134055251329 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 162000, while the sum is 40.
The spelling of 134055251329 in words is "one hundred thirty-four billion, fifty-five million, two hundred fifty-one thousand, three hundred twenty-nine".
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