Base | Representation |
---|---|
bin | 1100001100010011100010… |
… | …0001011010101110101110 |
3 | 1202110120001012211210110001 |
4 | 3003010320201122232232 |
5 | 3224114022022341100 |
6 | 44302230504134514 |
7 | 2552342544142540 |
oct | 303047041325656 |
9 | 52416035753401 |
10 | 13405541215150 |
11 | 42a9292597047 |
12 | 160610076743a |
13 | 7631a230b096 |
14 | 344b900cd690 |
15 | 183a97791d6a |
hex | c313885abae |
13405541215150 has 384 divisors, whose sum is σ = 31998135988224. Its totient is φ = 4070496460800.
The previous prime is 13405541215147. The next prime is 13405541215151. The reversal of 13405541215150 is 5151214550431.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13405541215151) by changing a digit.
It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 5412005712 + ... + 5412008188.
It is an arithmetic number, because the mean of its divisors is an integer number (83328479136).
Almost surely, 213405541215150 is an apocalyptic number.
13405541215150 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13405541215150 is an abundant number, since it is smaller than the sum of its proper divisors (18592594773074).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13405541215150 is a wasteful number, since it uses less digits than its factorization.
13405541215150 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3164 (or 3159 counting only the distinct ones).
The product of its (nonzero) digits is 60000, while the sum is 37.
Adding to 13405541215150 its reverse (5151214550431), we get a palindrome (18556755765581).
The spelling of 13405541215150 in words is "thirteen trillion, four hundred five billion, five hundred forty-one million, two hundred fifteen thousand, one hundred fifty".
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