1340605103490 has 192 divisors, whose sum is σ = 3673908935424. Its totient is φ = 351680237568.

The previous prime is 1340605103477. The next prime is 1340605103503. The reversal of 1340605103490 is 943015060431.

1340605103490 is a `hidden beast` number, since 1 + 3 + 4 + 0 + 60 + 5 + 103 + 490 = 666.

It is an interprime number because it is at equal distance from previous prime (1340605103477) and next prime (1340605103503).

It is a super-2 number, since 2×1340605103490² (a number of 25 digits) contains 22 as substring.

It is a Curzon number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 39346542 + ... + 39380598.

It is an arithmetic number, because the mean of its divisors is an integer number (19134942372).

Almost surely, 2^{1340605103490} is an apocalyptic number.

1340605103490 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is a practical number, because each smaller number is the sum of distinct divisors of 1340605103490, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1836954467712).

1340605103490 is an abundant number, since it is smaller than the sum of its proper divisors (2333303831934).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1340605103490 is a wasteful number, since it uses less digits than its factorization.

1340605103490 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 34343 (or 34331 counting only the distinct ones).

The product of its (nonzero) digits is 38880, while the sum is 36.

The spelling of 1340605103490 in words is "one trillion, three hundred forty billion, six hundred five million, one hundred three thousand, four hundred ninety".