Base | Representation |
---|---|
bin | 11000111110001010… |
… | …11100010000010101 |
3 | 1021121022112210200112 |
4 | 30133011130100111 |
5 | 204424021001122 |
6 | 10054150052405 |
7 | 653136464351 |
oct | 143705342025 |
9 | 37538483615 |
10 | 13406422037 |
11 | 575a637338 |
12 | 272194a105 |
13 | 1358651408 |
14 | 912722461 |
15 | 536e832e2 |
hex | 31f15c415 |
13406422037 has 16 divisors (see below), whose sum is σ = 14737738752. Its totient is φ = 12140117760.
The previous prime is 13406422033. The next prime is 13406422067. The reversal of 13406422037 is 73022460431.
It is a cyclic number.
It is not a de Polignac number, because 13406422037 - 22 = 13406422033 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13406421994 and 13406422012.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13406422033) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 17648 + ... + 164694.
It is an arithmetic number, because the mean of its divisors is an integer number (921108672).
Almost surely, 213406422037 is an apocalyptic number.
13406422037 is a gapful number since it is divisible by the number (17) formed by its first and last digit.
It is an amenable number.
13406422037 is a deficient number, since it is larger than the sum of its proper divisors (1331316715).
13406422037 is a wasteful number, since it uses less digits than its factorization.
13406422037 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 147268.
The product of its (nonzero) digits is 24192, while the sum is 32.
Adding to 13406422037 its reverse (73022460431), we get a palindrome (86428882468).
The spelling of 13406422037 in words is "thirteen billion, four hundred six million, four hundred twenty-two thousand, thirty-seven".
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